Answer:
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Here t1 = 1; t2
=2; t3 = 4 ; t4 = 7 and t5 = 11
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∴ t2 – t1 = 2 – 1 = 1
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∴ t3 – t 2 = 4 – 2 = 2
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∴ t4 – t3 = 7 – 4 = 3
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∴ t5 – t4 = 11 – 7 = 4
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∴ Here the difference between any two consecutive
term is go on increasing by 1.
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∴ t6 = t5 + 5 = 11 + 5 = 16
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∴ t7 = t6 + 6 = 16 + 6 = 22
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∴ the next two terms are 16 and 22.
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