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0.5, 2, 3.5, 5, ...


(vi) 0.5, 2, 3.5, 5, ... (1 mark)

Sol. t1 = 0.5, t2 = 2, t3 = 3.5, t4 = 5

t2 – t1 = 2 – 0.5 = 1.5
t3 – t2 = 3.5 – 2 = 1.5
t4 – t3 = 5 – 3.5 = 1.5

Here, The difference between ANY two consecutive terms is 1.5 which is constant.


The sequence is an A.P.