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3x2 + 2x – 1 = 0
(ii) 3x
2
+ 2x – 1 = 0
Sol.
3x
2
+ 2x – 1 = 0
Comparing with ax
2
+ bx + c = 0 we have a = 3, b = 2, c = – 1
∆
= b
2
– 4ac
= (2)
2
– 4 (3) (– 1)
= 4 + 12
= 16
∴ ∆ = 16
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