Advertisement

3y2 + 9y + 4 = 0

(v) 3y2 + 9y + 4 = 0
Sol. 3y2 + 9y + 4 = 0
Comparing with ay2 + by + c = 0 we have a = 3, b = 9, c = 4
 = b2 – 4ac
= (9)2 – 4 (3) (4)
= 81 – 48
= 33
∴ ∆  > 0

Hence roots of the quadratic equation are real and unequal.