a = 3, d = 4

(v) a = 3, d = 4 (1 mark)

Sol. a = 3, d = 4

Here, t1 = a = 3

t2 = t1 + d = 3 + 4 = 7

t3 = t2 + d = 7 + 4 = 11

t4 = t3 + d = 11 + 4 = 15

t5 = t4 + d = 15 + 4 = 19

∴   The first five terms of the A.P. are 3, 7, 11, 15 and 19.