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a = 5, d = 2
(iv) a = 5, d = 2 (1 mark)
Sol. a = 5, d = 2
Here, t1 = a = 5
t2 = t1 + d = 5 + 2 = 7
t3 = t2 + d = 7 + 2 = 9
t4 = t3 + d = 9 + 2 = 11
t5 = t4 + d = 11 + 2 = 13
∴
The first five terms of the A.P. are 5, 7, 9, 11 and 13.
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