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Solution:
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The given quadratic
equation is x2 – 4√3x + 4 = 0
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By comparing with
standard quadratic equation of ax2 + bx + c = 0, we get
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a = 1, b = - 4√3 , c = 4
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Now, Discriminant = ∆ =
b2 – 4ac = ( - 4 √3 )2 – 4(1)(4)
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∴ ∆ = 16(3) – 16
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∴ ∆ = 48 – 16
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∴ ∆ = 32
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∴ The Discriminant is 32.
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Find the value of discriminant for the following. x2 - 4 √ 3 x + 4 = 0 .
