(iv) 192, – 96, 48, – 24, .... (1 mark)

(iv) 192, – 96, 48, – 24, .... (1 mark)

Sol. t₁ = 192

t₂ = ¹⁹² / _–2 = – 96

t₃ = ^–96 / _{– 2} = 48

t₄ = ⁴⁸ / _{– 2} = – 24

t₅ = ^–24 / _{– 2} = 12

t₆ = ¹² / _{– 2} = – 6

t₇ = ^{– 6} / _{– 2} = 3

t₈ = ³/ _{– 2} = ³/ _{– 2}

∴  The next four terms of the sequence are 12, – 6, 3 and ³/_–2