(v) p2 – 12p + 32 = 0
Sol. p2 – 12p + 32 = 0
∴ p2 – 12p = –32 .... (i)
Third term = ( ½ × coefficient of p)2
= ( ½ × - 12)2
= (– 6)2
= 36
Adding 36 to both sides of (i), we get,
p2 – 12p + 36 = – 32 + 36
∴ (p – 6)2 = 4
∴ p – 6 = ± √4
∴ p – 6 = ± 2
∴ p = 6 ± 2
∴ p = 6 + 2 or p = 6 – 2
∴ p = 8 or p = 4
