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x2 + 4x + 1 = 0
(i) x
2
+ 4x + 1 = 0
Sol.
x
2
+ 4x + 1 = 0
Comparing with ax
2
+ bx + c = 0 we have a = 1, b = 4, c = 1
∆ = b
2
– 4ac
= (4)
2
– 4 (1) (1)
= 16 – 4
= 12
∴ ∆ = 12
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