y2 = 3 + 4y

(iv) y² = 3 + 4y

Sol. y² = 3 + 4y

∴  y² – 4y = 3 .... (i)

Third term = ( ½ ×  coefficient of y)²

= ( ½ × - 4)²

= (-2)²

= 4

Adding 4 to both sides of (i) we get,

y² – 4y + 4 = 3 + 4

∴  (y – 2)² = 7

∴ y – 2 = ±√7

∴ y = 2 ±√7

∴  y = 2 +√7 or y = 2 – √7