(iv) y2 = 3 + 4y
Sol. y2 = 3 + 4y
∴ y2 – 4y = 3 .... (i)
Third term = ( ½ × coefficient of y)2
= ( ½ × - 4)2
= (-2)2
= 4
Adding 4 to both sides of (i) we get,
y2 – 4y + 4 = 3 + 4
∴ (y – 2)2 = 7
∴ y – 2 = ±√7
∴ y = 2 ±√7
∴ y = 2 +√7 or y = 2 – √7
