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y2 + 6y – 2 = 0
(ii) y
2
+ 6y – 2 = 0
Sol.
y
2
+ 6y – 2 = 0
Comparing with ay
2
+ by + c = 0 we have a = 1, b = 6, c = – 2
∆
= b
2
– 4ac
= (6)
2
– 4 (1) (– 2)
= 36 + 8
= 44
∆
> 0
Hence roots of the quadratic equation are real and unequal.
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