y2 + 8y + 4 = 0

(iii) y² + 8y + 4 = 0

Sol. y² + 8y + 4 = 0

Comparing with ay² + by + c = 0 we have a = 1, b = 8, c = 4

∆  = b² – 4ac

= (8)² – 4 (1) (4)

= 64 -16

= 48

∴  ∆  > 0

Hence roots of the quadratic equation are real and unequal.