(iii) y2 + 8y + 4 = 0
Sol. y2 + 8y + 4 = 0
Comparing with ay2 + by + c = 0 we have a = 1, b = 8, c = 4
∆ = b2 – 4ac
= (8)2 – 4 (1) (4)
= 64 -16
= 48
∴ ∆ > 0
Hence roots of the quadratic equation are real and unequal.