(i) 1/x + 1/y = 8;; 4/x – 2/y = 2
Let 1/x = a and 1/y = b
∴ We get, a + b = 8
......... eq. no. (1)
and 4a – 2b = 2
........ eq. no. (2)
Multiplying
(1) by 2, we get
2a
+ 2b = 16 ........ eq. no. (3)
Adding
eq. (2) and eq. (3)
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4a
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-2b
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=
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2
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2a
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+2b
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=
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16
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∴ 6a
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=
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18
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∴ a = 18/6
∴ a = 3
Substituting
a = 3 in eq. no. (1)
a
+ b = 8
∴ 3 + b = 8
∴ b = 8 – 3
∴ b = 5
Substituting
the values of a and b,
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a = 3
∴ 1/x = 3
∴ x = 1/3
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b = 5
∴ 1/y = 5
∴ y = 1/5
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