v. 2x + y = 6; 4 – 3x/4
= y
2x + y = 6
X
|
0
|
1
|
2
|
Y
|
6
|
4
|
2
|
(X,Y)
|
(0,6)
|
(1,4)
|
(2,2)
|
Put, x = 0
∴ 2(0) + y = 6
∴ y = 6
|
Put, x = 1
∴ 2(1) + y = 6
∴ 2 + y = 6
∴ y = 6 – 2
∴ y = 4
|
Put, x = 2
∴ 2(2) + y = 6
∴ 4 + y = 6
∴ y = 6 – 4
∴ y = 2
|
4 – 3x/4 = y
∴ 4 – 3x = 4y
X
|
0
|
4
|
-4
|
Y
|
1
|
-2
|
4
|
(X,Y)
|
(0,1)
|
(4,-2)
|
(-4,4)
|
Put, x = 0
∴ 4 – 3(0) = 4y
∴ 4 – 0 = 4y
∴ 4 = 4y
∴ 4/4 = y
∴ 1 = y
∴ y = 1
|
Put, x = 4
∴ 4 – 3(4) = 4y
∴ 4 – 12 = 4y
∴ - 8 = 4y
∴ -8/4 = y
∴ - 2 = y
∴ y = - 2
|
Put, x = - 4
∴ 4 – 3 ( - 4 ) = 4y
∴ 4 + 12 = 4y
∴ 16 = 4y
∴ 16/4 = y
∴ 4 = y
∴ y = 4
|
x = 4 and y = – 2 is
the solution of given simultaneous equations.
