(ii) 4 – 3√ 2
Sol. If one of
the root of the quadratic equation is 4 – 3√2 ,
then the other root is 4 + 3√ 2
Let α= 4 – 3√2
and β
= 4 + 3√2
∴ α + β = 4
– 3√2 + 4 + 3√2 = 8
and α β = (4 – 3√2) × (4 + 3√2)
= (4)2 –
(3√ 2)2
= 16 – 9 × 2
= 16 – 18
= – 2
We know that, Quadratic equation is given by,
x2 – (Sum of the roots)x + Product of
the roots = 0
∴ x2 –( α + β)x + αβ = 0
∴ x2 – (8)x + (-2) = 0
∴ x2 - 8x - 2 = 0
∴ The required
quadratic equation is x2 - 8x - 2 = 0