(iii) 4x = y – 5; y = 2x + 1
4x = y – 5
X
|
- 1
|
0
|
-2
|
Y
|
1
|
5
|
-3
|
(X,Y)
|
(-1,1)
|
(0,5)
|
(-2,-3)
|
Put x = - 1
∴ 4(-1) = y – 5
∴ -4 + 5 = y
∴ 1 = y
∴ y = 1
|
Put x = 0
∴ 4(0) = y – 5
∴ 0 = y – 5
∴ y = 5
|
Put x = - 2
∴ 4(-2) = y – 5
∴ - 8 = y – 5
∴ - 8 + 5 = y
∴ -3 = y
∴ y = - 3
|
y = 2x + 1
X
|
0
|
1
|
2
|
Y
|
1
|
3
|
5
|
(X,Y)
|
(0,1)
|
(1,3)
|
(2,5)
|
Put x = 0
∴ y = 2(0) + 1
∴ y = 1
|
Put x = 1
∴ y = 2(1) + 1
∴ y = 2 + 1
∴ y = 3
|
Put x = 2
∴ y = 2(2) + 1
∴ y = 4 + 1
∴ y = 5
|
x = - 2 and y = 3 is the solution of given simultaneous equations.
