(iv) x + 2y = 5; y = – 2x – 2
x + 2y = 5
X
|
5
|
3
|
1
|
Y
|
0
|
1
|
2
|
(X,Y)
|
(5,0)
|
(3,1)
|
(1,2)
|
Put, x = 5
∴ 5 + 2y = 5
∴ 2y = 5 – 5
∴ 2y = 0
∴ y = 0/2
∴ y = 0
|
Put, x = 3
∴ 3 + 2y = 5
∴ 2y = 5 – 3
∴ 2y = 2
∴ y = 2/2
∴ y = 1
|
Put, x = 1
∴ 1 + 2y = 5
∴ 2y = 5 – 1
∴ 2y = 4
∴ y = 4/2
∴ y = 2
|
y = – 2x – 2
X
|
0
|
1
|
2
|
Y
|
-
2
|
-4
|
-6
|
(X,Y)
|
(0,-2)
|
(1,-4)
|
(2,-6)
|
Put x = 0
∴ y = -2(0) – 2
∴ y = -2
|
Put x = 1
∴ y = - 2(1) – 2
∴ y = - 2 – 2
∴ y = - 4
|
Put x = 2
∴ y = - 2(2) -2
∴ y = - 4 – 2
∴ y = - 6
|
x = - 3 and y = 4 is
the solution of given simultaneous equations.
