Solution: sinθ = 5/13 [Given]
∴ cosecθ = 1/sinθ = 1÷ (5/13)
∴ cosec θ = 13/5
We know that,
sin2θ + cos2θ = 1
∴ (5/13)2 + cos2θ = 1
∴ 25/169 + cos2θ = 1
∴ cos2θ= 1 – 25/169
∴ cos2θ = (169 – 25 )/169
∴ cos2θ= 144/169
∴ cosθ = ±√ (144/169)
∴ cosθ = ±12/13
But, θ is an acute angle [Given]
∴ All trigonometric ratios must be
positive,
∴ cosθ = 12/13
secθ = 1/cosθ
∴ sec θ = 1÷ (12/13)
∴ secθ = 13/12
tanθ = sinθ ÷ cosθ
∴ tanθ = 5/13 ÷ 12/13
∴ tan θ = 5/13 × 13/12.
∴ tanθ = 5/12
cotθ = 1/tanθ
∴ cot θ = 1÷ (5/12)
∴ cot θ = 12/5