Ans. Data Given: Power = 750 W,
Time = 2 hours per day,
No. of days = 30 days.
Solution: Energy consumed = Power Rating x time of operation.
Therefore, Energy consumed = 750 W x 2 hrs x 30 days = 45000 W hour
Therefore, Energy consumed = (45000 / 1000 ) kWh.
Therefore, Energy consumed = 45 kWh.
Therefore, Energy consumed by the electric iron is 45 kWh.
