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Solution:
Comparing the given equation 2y2 + 5 y – 3 = 0 with the standard
quadratic equation ax2 + bx + c = 0 we get,
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a
= 2, b = 5 and c = - 3
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Discriminant
∆ = b2 – 4ac
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∴ ∆ = 52 – 4
(2) (-3)
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∴ ∆ = 25 + 24
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∴ ∆ = 49
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∵ ∆ > 0
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∴ the nature of the root is real and
unequal.
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Determine the nature of the roots of the equation 2y2 + 5y – 3 = 0 from its discriminant.
