Answer:
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Since the temperature
at hill station from Monday to Friday is in A.P.
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∴ Let us assume those 5
days temperature be
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Monday = a – 2d
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Tuesday = a – d
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Wednesday = a
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Thursday = a + d
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Friday = a + 2d
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According to first condition
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a – 2d + a – d + a = 0
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∴ 3a – 3d = 0 ------------- eq. no. (1)
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According to second condition
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a + d + a + 2d = 15
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∴ 2a + 3d = 15 -------------eq. no. (2)
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Adding eq. (1) and eq. (2)
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3a – 3d = 0
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2a + 3d = 15
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5a + 0 =
15
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∴ a = 15/5
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∴ a = 3
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Substituting a = 3 in
eq. (2)
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2a + 3d = 15
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∴ 2(3) + 3d = 15
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∴ 6 + 3d = 15
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∴ 3d = 15 – 6
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∴ 3d = 9
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∴ d = 9/3
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∴ d = 3
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Monday = a – 2d = 3 – 2(3) = 3 – 6 = - 30 C
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Tuesday = a – d = 3 – 3 =
00 C
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Wednesday = a = 3 0 C
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Thursday = a + d = 3 + 3 = 60 C
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Friday = a + 2d = 3 + 2(3) = 3 + 6 = 90 C
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∴ The temperature from Monday to Friday are
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- 3 0 C, 00 C, 30 C, 60C
and 90C respectively.
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