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Answer.
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Given
equation is x4 - 3x2 + 2 = 0
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Put x2 = a
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∴ a2 – 3a + 2 = 0
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∴ a2 – 2a –
a + 2 = 0
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∴ a(a – 2) – 1 (a – 2)
= 0
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∴ (a – 2 ) (a – 1) = 0
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∴ a – 2 = 0
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OR
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a
– 1 = 0
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∴ a = 2
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∴ a = 1
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Re substituting the value of a = x2
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∴ x2 = 2
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x2 = 1
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∴ x = ± √2
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∴ x = ± 1
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