|
Solution:
|
|
The given equation is
|
|
y + 1/y
= 3
|
|
Multiplying with y on
both the sides we get,
|
|
∴ y2 + y/y
= 3
|
|
∴ y2 + 1 = 3
|
|
∴ y2 +1 – 3 = 0
|
|
∴ y2 – 2 = 0
|
|
But, it can be written as y2 + 0x – 2 = 0
|
|
Now, it is in the form of ax2 + bx + c = 0,
|
|
where a = 1, b = 0 and c = - 2 ,
|
|
Here a, b and c are belongs to Real numbers, where a is not
equal to zero
|
|
∴ It is a quadratic eqution.
|
State whether the given equation is quadratic or not: y + 1/y = 3.
