(i) 3x + 5y = 16; 4x – y = 6
Sol. 3x + 5y = 16
Comparing
with a1x
+ b1y
= c1 we
get, a1 =
3, b1 =
5, c1 =
16
4x
– y = 6
Comparing
with a2x + b2y = c2 we
get, a2 = 4, b2
= – 1, c2 =
6
a1/a2
= 3/6 = ½ ............ eq. no. (i)
b1/b2
= 5/-1 = - 5 ............ eq. no. (ii)
c1/c2
= 16/6 = 8/3 ............ eq. no. (iii)
From
Equation (i) , (ii) and (iii) we get
a1/a2
≠ b1/b2
∴
Unique Solution.
