∆ PBS ∼ ∆ FOX

1. ∆ PBS ∼ ∆ FOX

These corresponding angles are congruent:

∠ P≅ ∠ F

∠ B≅ ∠ O

∠ S ≅ ∠ X

These corresponding sides are proportional:

^PB/_FO = ^BS/_OX = ^PS/_FX