Solution: Let
the two numbers be x and y such that x > y.
Then
from the first condition,
x
+ y = 60 ............. eq. no. (1)
From
the second condition,
x
= 3y + 8
∴
x – 3y = 8 ............... eq. no. (2)
Subtracting
equation (2) from equation (1),
|
x
+ y = 60
|
|
x
– 3y = 8
|
|
(-) (+)
(-)
|
|
4y = 52
|
∴
y = 52/4
∴
y = 13
Substituting
y = 13 in equation (1),
x
+ y = 60
∴
x + 13 = 60
∴
x = 60 – 13
∴
x = 47
∴ The greater number is 47 and the smaller number is
13.
