2. If the angle θ = – 60º, find the value of sin θ , cos θ, sec θ and tan θ.

Sol. θ = – 60º

sin (–θ) = – sin θ

∴  sin (– 60) = – sin 60

∴  sin (– 60) = - √3/2

sec (–θ) = sec θ

∴  sec (– 60)= sec 60

∴ sec (– 60)= 2

cos (–θ) = cos θ

∴  cos (– 60)= cos 60

∴  cos (– 60)= 1/2

tan (–θ) = – tan θ

∴  tan (– 60)= – tan 60

∴  tan (– 60)= – √3