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Practice Set 1.1 Linear Equations In Two Variables Class 10th Mathematics Part 1 MHB Solution

Practice Set 1.1

Complete the following activity to solve the simultaneous equations. 5x + 3y = 9 . (i)…

3a + 5b = 26; a + 5b = 22 Solve the following simultaneous equation.…

x + 7y = 10; 3x - 2y = 7 Solve the following simultaneous equation.…

2x - 3y = 9; 2x + y = 13 Solve the following simultaneous equation.…

5m - 3n = 19; m - 6n = -7 Solve the following simultaneous equation.…

5x + 2y = -3; x + 5y = 4 Solve the following simultaneous equation.…

1/3 x+y = 10/3 2x + 1/4 y = 11/4 Solve the following simultaneous equation.…

99x + 101 y = 499; 101x + 99y = 501 Solve the following simultaneous equation.…

49x - 57y = 172; 57x - 49y = 252 Solve the following simultaneous equation.…


Practice Set 1.1
Question 1.

Complete the following activity to solve the simultaneous equations.
5x + 3y = 9 ……. (i)
2x + 3y = 12 ……… (ii)


Answer:

5x + 3y = 9 ……. (i)

2x + 3y = 12 ……… (ii)

Subtracting equation (ii) from (i), we get,

(5x + 3y ) - (2x + 3y) = 9 - 12

5x - 2x + 3y - 3y = -3

3x = -3

x = -1

Putting the value of x in equation (i),

5(-1) + 3y = 9

-5 + 3y = 9

3y = 14

y = 14/3

Let’s add equations (I) and (II).

Hence, x = -1 and y = 14/3 is the solution of the equation.



Question 2.

Solve the following simultaneous equation.

3a + 5b = 26; a + 5b = 22


Answer:



Change the sign of Eq. (II)







Substituting a = 2 in Eq. (II)







∴ solution is (a, b) = (2, 4)



Question 3.

Solve the following simultaneous equation.

x + 7y = 10; 3x – 2y = 7


Answer:



Multiply Eq. I by 2 and Eq. II by 7






x=3


Substituting x= 3 in Eq. I




7y=7



y=1


∴ Solution is (x , y) = (3, 1)


Question 4.

Solve the following simultaneous equation.

2x – 3y = 9; 2x + y = 13


Answer:



Change the sign of Eq. (II)





Substituting y = 1 in Eq. (II)



2x = 13 - 1
2x = 12
x = 6


∴ solution is (x, y) = (1,6)


Question 5.

Solve the following simultaneous equation.

5m – 3n = 19; m – 6n = –7


Answer:



Multiply Eq. II by 5



equating (I) and (III), change the sign of Eq. (III)



Adding both we get

⇒ 


⇒ 


⇒ n = 2


Substituting n = 2 in Eq 1
⇒ 5m - 3(2) = 19
⇒ 5m - 6 = 19
⇒ 5m = 25
⇒ m = 5

∴ Solution is (m , n) = (5, 2)


Question 6.

Solve the following simultaneous equation.

5x + 2y = –3; x + 5y = 4


Answer:



Multiply Eq. I by 5 and Eq. II by 2




Change sign of Eq.(IV)





Subsituting x=–1in Eq.II







∴ solution is (x, y) = (–1, 1)



Question 7.

Solve the following simultaneous equation.



Answer:

 ⇒  ⇒ 


 ⇒  ⇒ 


Multiplying Eq. II by 3



Equating Eq. I and III, change the signs of Eq. III






Substituting x = 1 in Eq. I







∴ solution is (x,y) = (1, 3)



Question 8.

Solve the following simultaneous equation.

99x + 101 y = 499; 101x + 99y = 501


Answer:



Adding both the Equations



Dividing both sides by 200


 …(III)


Subtract equation (I) and (II)



Divide both sides by (–2)


 …(IV)


Equating Eq. (III) and (IV)





Substituting x=3 in Eq. III





∴ solution is (x, y) = (3, 2)



Question 9.

Solve the following simultaneous equation.

49x – 57y = 172; 57x – 49y = 252


Answer:



Adding both the Equations



Dividing both sides by 106


 …(III)


Subtract equation (I) and (II)



Divide both sides by (–8)


 …(IV)


Equating Eq. (III) and (IV)





Substituting x=7 in Eq. IV





∴ solution is (x, y) = (7,3)