Practice Set 6.2
- The following table shows classification of number of workers and the number of hours…
- The frequency distribution table shows the number of mango trees in a grove and their…
- The following table shows the classification of number of vehicles and their speeds on…
- The production of electric bulbs in different factories is shown in the following…
Practice Set 6.2
Question 1.
The following table shows classification of number of workers and the number of hours they work in a software company. Find the median of the number of hours they work.
Answer:
⇒ N = 1000
⇒ 500 Lies in class 10-12
⇒ Median class 10-12
L = lower limit of median class = 10
N = sum of frequencies = 1000
h = class interval of median class = 2
f = frequency of median class = 500
cf = cumulative frequency of class preceding median class = 150
⇒ Median 
⇒ Median 
⇒ Median = 11.4
Question 2.
The frequency distribution table shows the number of mango trees in a grove and their yield of mangoes. Find the median of data.
Answer:
⇒ N = 250
⇒ 125 Lies in class 100-150
⇒ Median class 100-150
L = lower limit of median class = 100
N = sum of frequencies = 250
h = class interval of median class = 50
f = frequency of median class = 30
cf = cumulative frequency of class preceding median class = 33
⇒ Median
⇒ Median =
⇒ Median = 253.33
Question 3.
The following table shows the classification of number of vehicles and their speeds on Mumbai-Pune express way. Find the median of the data.
Answer:
The class is discontinuous between 69-74 and 75-79
Converting the to continuous class
⇒ N = 200
⇒ 100 Lies in class 74.5-79.5
⇒ Median class 74.5-79.5
L = lower limit of median class = 74.5
N = sum of frequencies = 200
h = class interval of median class = 5
f = frequency of median class = 85
cf = cumulative frequency of class preceding median class = 99
⇒ Median
⇒ Median 
⇒ Median = 74.558
Question 4.
The production of electric bulbs in different factories is shown in the following table. Find the median of the productions.
Answer:
⇒ N = 105
⇒ 52.5 Lies in class 50-60
⇒ Median class 50-60
L = lower limit of median class = 50
N = sum of frequencies = 105
h = class interval of median class = 10
f = frequency of median class = 20
cf = cumulative frequency of class preceding median class = 47
⇒ Median
⇒ Median 
⇒ Median = 52.75
⇒ In thousands = 52.75× 1000 = 52750 lamps
