Class 12th Mathematics Part I CBSE Solution
Exercise 2.1- sin^-1 (- 1/2) Find the principal values of the following:
- cos^-1 (root 3/2) Find the principal values of the following:
- cosec-1 (2) Find the principal values of the following:
- tan^-1 (- root 3) Find the principal values of the following:
- cos^-1 (- 1/2) Find the principal values of the following:
- tan-1 (-1) Find the principal values of the following:
- sec^-1 (2/root 3) Find the principal values of the following:
- cot^-1 (- root 3) Find the principal values of the following:
- cos^-1 (- 1/root 2) Find the principal values of the following:
- cosec^-1 (- root 2) Find the principal values of the following:
- Find the values of the following:
- cos^-1 (1/2) + 2sin^-1 (1/2) Find the values of the following:
- sin-1 x = y, then Find the values of the following:A. 0 ≤ y ≤ π B. - pi /2 less…
- tan^-1root 3-sec^-1 (-2) is equal to Find the values of the following:A. π B. -…
Exercise 2.2- 3sin^-1x = sin^-1 (3x-4x^3) , x in[- 1/2 , 1/2] Prove the following:…
- 3cos^-1x = cos^-1 (4x^3 - 3x) , x in[1/2 , 1] Prove the following:…
- tan^-1 2/11 + tan^-1 7/24 = tan^-1 1/2 Prove the following:
- 2tan^-1 1/2 + tan^-1 1/7 = tan^-1 31/17 Prove the following:
- tan^-1 root 1+x^2 -1/x , x not equal 0 Write the following functions in the…
- tan^-1 1/root x^2 - 1 , |x|1 Write the following functions in the simplest form:…
- Write the following functions in the simplest form:
- tan^-1 (cosx-sinx/cosx+sinx) , 0x pi Write the following functions in the…
- tan^-1 x/root a^2 -x^2 , |x|a Write the following functions in the simplest…
- tan^-1 (3a^3x-x^3/a^3 - 3ax^2) , a0 -a/root 3 x a/root 3 Write the following…
- tan^-1 [2cos (2sin^-1 1/2)] Find the values of each of the following:…
- cot (tan-1a + cot-1a) Find the values of each of the following:
- tan 1/2 [sin^-1 2x/1+x^2 + cos^-1 1-y^2/1+y^2] , |x|1 , y = 0 xy1 Find the…
- If sin (sin^-1 1/5 + cos^-1x) = 1 , then find the value of x Find the values of…
- tan^-1 x-1/x-2 + tan^-1 x+1/x+2 = pi /4 , then find the value of x. Find the…
- sin^-1 (sin 2 pi /3) Find the values of each of the expression
- tan^-1 (tan 3 pi /4) Find the values of each of the expression
- tan (sin^-1 3/5 +cot^-1 3/2) Find the values of each of the expression…
- cos^-1 (cos 7 pi /6) is equal to Find the values of each of the expressionA. 7…
- sin (pi /3 - sin^-1 (- 1/2)) is equal to Find the values of each of the…
- tan^-1root 3-cot^-1 (- root 3) is equal to Find the values of each of the…
Miscellaneous Exercise- cos^-1 (cos 13 pi /6) Find the value of the following:
- tan^-1 (tan 7 pi /6) Find the value of the following:
- Prove that
- sin^-1 8/17 + sin^-1 3/5 = tan^-1 77/36 Prove that
- cos^-1 4/5 + cos^-1 12/13 = cos^-1 33/65 Prove that
- cos^-1 12/13 + sin^-1 3/5 = sin^-1 56/65 Prove that
- tan^-1 63/16 = sin^-1 5/13 + cos^-1 3/5 Prove that
- tan^-1 1/5 + tan^-1 1/7 + tan^-1 1/3 + tan^-1 1/8 = pi /4 Prove that…
- tan^-1root x = 1/2 cos^-1 (1-x/1+x) , x in[0 , 1] Prove that
- cot^-1 (root 1+sinx+ root 1-sinx/root 1+sinx- root 1-sinx) = x/2 , x in (0 , pi…
- Prove that tan^-1 (root 1+x + root 1-x/root 1+x - root 1-x) = pi /4 - 1/2…
- 9 pi /8 - 9/4 sin^-1 1/3 = 9/4 sin^-1 2 root 2/3 Prove that
- 2tan^-1 (cosx) = tan^-1 (2cosecx) Solve the following equations:
- tan^-1 1-x/1+x = 1/2 tan^-1x , (x0) Solve the following equations:…
- sin (tan^-1x) , |x|1 is equal to Solve the following equations:A. x/root 1+x^2…
- sin^-1 (1-x) -2sin^-1x = pi /2 , then x is equal to Solve the following…
- tan^-1 (x/y) - tan^-1 x-y/x+y is equal to Solve the following equations:A. pi…
- sin^-1 (- 1/2) Find the principal values of the following:
- cos^-1 (root 3/2) Find the principal values of the following:
- cosec-1 (2) Find the principal values of the following:
- tan^-1 (- root 3) Find the principal values of the following:
- cos^-1 (- 1/2) Find the principal values of the following:
- tan-1 (-1) Find the principal values of the following:
- sec^-1 (2/root 3) Find the principal values of the following:
- cot^-1 (- root 3) Find the principal values of the following:
- cos^-1 (- 1/root 2) Find the principal values of the following:
- cosec^-1 (- root 2) Find the principal values of the following:
- Find the values of the following:
- cos^-1 (1/2) + 2sin^-1 (1/2) Find the values of the following:
- sin-1 x = y, then Find the values of the following:A. 0 ≤ y ≤ π B. - pi /2 less…
- tan^-1root 3-sec^-1 (-2) is equal to Find the values of the following:A. π B. -…
- 3sin^-1x = sin^-1 (3x-4x^3) , x in[- 1/2 , 1/2] Prove the following:…
- 3cos^-1x = cos^-1 (4x^3 - 3x) , x in[1/2 , 1] Prove the following:…
- tan^-1 2/11 + tan^-1 7/24 = tan^-1 1/2 Prove the following:
- 2tan^-1 1/2 + tan^-1 1/7 = tan^-1 31/17 Prove the following:
- tan^-1 root 1+x^2 -1/x , x not equal 0 Write the following functions in the…
- tan^-1 1/root x^2 - 1 , |x|1 Write the following functions in the simplest form:…
- Write the following functions in the simplest form:
- tan^-1 (cosx-sinx/cosx+sinx) , 0x pi Write the following functions in the…
- tan^-1 x/root a^2 -x^2 , |x|a Write the following functions in the simplest…
- tan^-1 (3a^3x-x^3/a^3 - 3ax^2) , a0 -a/root 3 x a/root 3 Write the following…
- tan^-1 [2cos (2sin^-1 1/2)] Find the values of each of the following:…
- cot (tan-1a + cot-1a) Find the values of each of the following:
- tan 1/2 [sin^-1 2x/1+x^2 + cos^-1 1-y^2/1+y^2] , |x|1 , y = 0 xy1 Find the…
- If sin (sin^-1 1/5 + cos^-1x) = 1 , then find the value of x Find the values of…
- tan^-1 x-1/x-2 + tan^-1 x+1/x+2 = pi /4 , then find the value of x. Find the…
- sin^-1 (sin 2 pi /3) Find the values of each of the expression
- tan^-1 (tan 3 pi /4) Find the values of each of the expression
- tan (sin^-1 3/5 +cot^-1 3/2) Find the values of each of the expression…
- cos^-1 (cos 7 pi /6) is equal to Find the values of each of the expressionA. 7…
- sin (pi /3 - sin^-1 (- 1/2)) is equal to Find the values of each of the…
- tan^-1root 3-cot^-1 (- root 3) is equal to Find the values of each of the…
- cos^-1 (cos 13 pi /6) Find the value of the following:
- tan^-1 (tan 7 pi /6) Find the value of the following:
- Prove that
- sin^-1 8/17 + sin^-1 3/5 = tan^-1 77/36 Prove that
- cos^-1 4/5 + cos^-1 12/13 = cos^-1 33/65 Prove that
- cos^-1 12/13 + sin^-1 3/5 = sin^-1 56/65 Prove that
- tan^-1 63/16 = sin^-1 5/13 + cos^-1 3/5 Prove that
- tan^-1 1/5 + tan^-1 1/7 + tan^-1 1/3 + tan^-1 1/8 = pi /4 Prove that…
- tan^-1root x = 1/2 cos^-1 (1-x/1+x) , x in[0 , 1] Prove that
- cot^-1 (root 1+sinx+ root 1-sinx/root 1+sinx- root 1-sinx) = x/2 , x in (0 , pi…
- Prove that tan^-1 (root 1+x + root 1-x/root 1+x - root 1-x) = pi /4 - 1/2…
- 9 pi /8 - 9/4 sin^-1 1/3 = 9/4 sin^-1 2 root 2/3 Prove that
- 2tan^-1 (cosx) = tan^-1 (2cosecx) Solve the following equations:
- tan^-1 1-x/1+x = 1/2 tan^-1x , (x0) Solve the following equations:…
- sin (tan^-1x) , |x|1 is equal to Solve the following equations:A. x/root 1+x^2…
- sin^-1 (1-x) -2sin^-1x = pi /2 , then x is equal to Solve the following…
- tan^-1 (x/y) - tan^-1 x-y/x+y is equal to Solve the following equations:A. pi…
Exercise 2.1
Question 1.Find the principal values of the following:
Answer:Let us take = x
Therefore,
We know that principle value range of sin-1 is
And,
Therefore principle value of is
Question 2.Find the principal values of the following:
Answer:Let us take
Then,
We know that principle value range of cos-1 is [0, π]
And
Therefore, principle value of is
Question 3.Find the principal values of the following:
cosec–1 (2 )
Answer:Let cosec-1 2 = x
Therefore,
And
We know that principle value range of cosec-1 is
Therefore, principle value of cosec-1(2) is .
Question 4.Find the principal values of the following:
Answer:Let us take
Then we get,
And
We know that principle value range of tan-1 is
Therefore, principle value of tan-1 is.
Question 5.Find the principal values of the following:
Answer:Let us take
Then we will get,
And
We know that principle value range of cos-1 is [0, π]
Therefore principle value of cos-1is
Question 6.Find the principal values of the following:
tan–1 (–1)
Answer:Let us take tan-1(-1) = x then we get,
And
We know that principle value range of tan-1 is
Therefore, principle value of tan-1(-1) is
Question 7.Find the principal values of the following:
Answer:Let
Then,
We know that range of the principle value branch of sec-1 is [0, π]
And
Therefore principle value of is
Question 8.Find the principal values of the following:
Answer:Let us consider
Then we get,
We know that the range of the principal value branch of cot-1 is [0, π].
And,
Therefore, the principle value of is .
Question 9.Find the principal values of the following:
Answer:Let
Therefore,
We know that range of the principle value branch of cos-1 is [0, π]
And
Therefore principle value of is
Question 10.Find the principal values of the following:
Answer:Let us take the values of
Then,
We know that range of the principle value branch of cosec-1 is
And
Therefore principle value of is
Question 11.Find the values of the following:
Answer:Let us consider tan-1(1) = x then we get
We know that range of the principle value branch of tan-1 is
Therefore,
Let
We know that range of the principle value branch of cos-1 is [0, π]
Therefore,
Let
We know that range of the principle value branch of sin-1 is
Therefore
Now,
Question 12.Find the values of the following:
Answer:Let
Then, we get,
We know that range of the principle value branch of cos-1 is [0, π]
Therefore
Let
We know that range of the principle value branch of sin-1 is
Therefore
Now,
Question 13.Find the values of the following:
sin–1 x = y, then
A. 0 ≤ y ≤ π
B.
C. 0 < y < π
D.
Answer:sin–1 x = y
We know that range of the principle value branch of sin-1 is
Therefore,
Hence, the option (B) is correct.
Question 14.Find the values of the following:
is equal to
A. π
B.
C.
D.
Answer:Let us take
Then we get,
We know that range of the principle value branch of tan-1 is
Therefore,
Let Then we get,
We know that range of the principle value branch of sec-1 is [0, π]
Therefore,
Now,
Hence, the option (B) is correct.
Find the principal values of the following:
Answer:
Let us take = x
Therefore,
We know that principle value range of sin-1 is
And,
Therefore principle value of is
Question 2.
Find the principal values of the following:
Answer:
Let us take
Then,
We know that principle value range of cos-1 is [0, π]
And
Therefore, principle value of is
Question 3.
Find the principal values of the following:
cosec–1 (2 )
Answer:
Let cosec-1 2 = x
Therefore,
And
We know that principle value range of cosec-1 is
Therefore, principle value of cosec-1(2) is .
Question 4.
Find the principal values of the following:
Answer:
Let us take
Then we get,
And
We know that principle value range of tan-1 is
Therefore, principle value of tan-1 is.
Question 5.
Find the principal values of the following:
Answer:
Let us take
Then we will get,
And
We know that principle value range of cos-1 is [0, π]
Therefore principle value of cos-1is
Question 6.
Find the principal values of the following:
tan–1 (–1)
Answer:
Let us take tan-1(-1) = x then we get,
And
We know that principle value range of tan-1 is
Therefore, principle value of tan-1(-1) is
Question 7.
Find the principal values of the following:
Answer:
Let
Then,
We know that range of the principle value branch of sec-1 is [0, π]
And
Therefore principle value of is
Question 8.
Find the principal values of the following:
Answer:
Let us consider
Then we get,
We know that the range of the principal value branch of cot-1 is [0, π].
And,
Therefore, the principle value of is .
Question 9.
Find the principal values of the following:
Answer:
Let
Therefore,
We know that range of the principle value branch of cos-1 is [0, π]
And
Therefore principle value of is
Question 10.
Find the principal values of the following:
Answer:
Let us take the values of
Then,
We know that range of the principle value branch of cosec-1 is
And
Therefore principle value of is
Question 11.
Find the values of the following:
Answer:
Let us consider tan-1(1) = x then we get
We know that range of the principle value branch of tan-1 is
Therefore,
Let
We know that range of the principle value branch of cos-1 is [0, π]
Therefore,
Let
We know that range of the principle value branch of sin-1 is
Therefore
Now,
Question 12.
Find the values of the following:
Answer:
Let
Then, we get,
We know that range of the principle value branch of cos-1 is [0, π]
Therefore
Let
We know that range of the principle value branch of sin-1 is
Therefore
Now,
Question 13.
Find the values of the following:
sin–1 x = y, then
A. 0 ≤ y ≤ π
B.
C. 0 < y < π
D.
Answer:
sin–1 x = y
We know that range of the principle value branch of sin-1 is
Therefore,
Hence, the option (B) is correct.
Question 14.
Find the values of the following:
is equal to
A. π
B.
C.
D.
Answer:
Let us take
Then we get,
We know that range of the principle value branch of tan-1 is
Therefore,
Let Then we get,
We know that range of the principle value branch of sec-1 is [0, π]
Therefore,
Now,
Hence, the option (B) is correct.
Exercise 2.2
Question 1.Prove the following:
Answer:Let
We have,
R.H.S =
Now, we know that,
sin 3x = 3sin x - 4 sin3x
Therefore,
= sin-1(sin (3θ))
= 3 θ
= 3sin-1x
= L.H.S
Hence Proved
Question 2.Prove the following:
Answer:Let x = cos θ
Then, Cos-1 = θ
Now, R.H.S. = cos-1(4x3 - 3x)
= cos-1(4cos3θ - 3cos θ)
= cos-1(cos3θ)
= 3θ
= 3cos-1x
= L.H.S.
Hence Proved
Question 3.Prove the following:
Answer:L.H.S.
= R.H.S.
Hence Proved.
Question 4.Prove the following:
Answer:L.H.S. =
= R.H.S.
Hence Proved.
Question 5.Write the following functions in the simplest form:
Answer:
Now, Put x = tanθ ⇒ θ =tan-1x
Therefore,
Therefore,
Question 6.Write the following functions in the simplest form:
Answer:Let us take,
[We have done this substitution on the bases of identity sec2θ – 1 = tan2θ]
Therefore,
Now we know that, cosec2θ – 1 = cot2θ
Therefore,
Question 7.Write the following functions in the simplest form:
Answer:Hence,
Question 8.Write the following functions in the simplest form:
Answer:
Dividing by cos x,
As we know tan(Π/4) = 1
Hence,
Question 9.Write the following functions in the simplest form:
Answer:We will solve this problem on the bases of the identity 1 - sin2θ = cos2θ
So, for a2 - x2, we can substitute x = a sinθ or x = a cosθ
Now, Let us put x = a sinθ
Therefore,
Hence,
Question 10.Write the following functions in the simplest form:
Answer:
Put
Now,
= 3θ
Question 11.Find the values of each of the following:
Answer:
We will solve the inner bracket first.
So, we will first find the principal value of
We know that,
Therefore,
= tan-11
= π/4
Hence,
The value of
Question 12.Find the values of each of the following:
cot (tan–1a + cot–1a)
Answer:
= 0
Hence, the value of cot(tan-1a + cot-1 a) = 0
Question 13.Find the values of each of the following:
Answer:
We will solve this problem by expressing sin2θ and cos2θ in terms of tanθ
Now let us put, x = tanθ. Then we will have,
θ = tan-1x
Now again, Let’s put, y = tan∅. Then we will have,
∅ = tan-1y
Now,
Hence, the value of
Question 14.Find the values of each of the following:
If , then find the value of x
Answer:
On comparing the co-efficient on both sides we get,
Question 15.Find the values of each of the following:
, then find the value of x.
Answer:
Question 16.Find the values of each of the expression
Answer:
(For type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range
So here,
Now, can be written as,
Hence, .
Question 17.Find the values of each of the expression
Answer:
(For type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range.)
So here,
Now, can be written as,
Hence,
Question 18.Find the values of each of the expression
Answer:Let and
, so all ratio of y are positive and
and
Also,
as
So,
Hence,
Question 19.Find the values of each of the expression
is equal to
A.
B.
C.
D.
Answer:
(For cos-1(cos x) type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range.)
So here,
Now, can be written as,
where [since, cos(π + x) = -cosx]
as cos-1(-x) = π – cos-1
Hence, .
Question 20.Find the values of each of the expression
is equal to
A.
B.
C.
D. 1
Answer:as
as
We all know that the principal value branch of sin-1 is
Therefore,
Hence, the value of
Question 21.Find the values of each of the expression
is equal to
A. π
B.
C. 0
D.
Answer:
Prove the following:
Answer:
Let
We have,
R.H.S =
Now, we know that,sin 3x = 3sin x - 4 sin3x
Therefore,
= sin-1(sin (3θ))
= 3 θ
= 3sin-1x
= L.H.S
Hence Proved
Question 2.
Prove the following:
Answer:
Let x = cos θ
Then, Cos-1 = θ
Now, R.H.S. = cos-1(4x3 - 3x)
= cos-1(4cos3θ - 3cos θ)
= cos-1(cos3θ)
= 3θ
= 3cos-1x
= L.H.S.
Hence Proved
Question 3.
Prove the following:
Answer:
L.H.S.
= R.H.S.
Hence Proved.
Question 4.
Prove the following:
Answer:
L.H.S. =
= R.H.S.
Hence Proved.
Question 5.
Write the following functions in the simplest form:
Answer:
Now, Put x = tanθ ⇒ θ =tan-1x
Therefore,
Therefore,
Question 6.
Write the following functions in the simplest form:
Answer:
Let us take,
[We have done this substitution on the bases of identity sec2θ – 1 = tan2θ]
Therefore,
Now we know that, cosec2θ – 1 = cot2θTherefore,
Question 7.
Write the following functions in the simplest form:
Answer:
Hence,
Question 8.
Write the following functions in the simplest form:
Answer:
Dividing by cos x,
As we know tan(Π/4) = 1
Hence,
Question 9.
Write the following functions in the simplest form:
Answer:
We will solve this problem on the bases of the identity 1 - sin2θ = cos2θ
So, for a2 - x2, we can substitute x = a sinθ or x = a cosθ
Now, Let us put x = a sinθ
Therefore,
Hence,
Question 10.
Write the following functions in the simplest form:
Answer:
Put
Now,
= 3θ
Question 11.
Find the values of each of the following:
Answer:
We will solve the inner bracket first.
So, we will first find the principal value of
We know that,
Therefore,
= tan-11
= π/4
Hence,
The value of
Question 12.
Find the values of each of the following:
cot (tan–1a + cot–1a)
Answer:
= 0
Hence, the value of cot(tan-1a + cot-1 a) = 0
Question 13.
Find the values of each of the following:
Answer:
We will solve this problem by expressing sin2θ and cos2θ in terms of tanθ
Now let us put, x = tanθ. Then we will have,
θ = tan-1x
Now again, Let’s put, y = tan∅. Then we will have,
∅ = tan-1y
Now,
Hence, the value of
Question 14.
Find the values of each of the following:
If , then find the value of x
Answer:
On comparing the co-efficient on both sides we get,
Question 15.
Find the values of each of the following:
, then find the value of x.
Answer:
Question 16.
Find the values of each of the expression
Answer:
(For type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range
So here,
Now, can be written as,
Hence, .
Question 17.
Find the values of each of the expression
Answer:
(For type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range.)
So here,
Now, can be written as,
Hence,
Question 18.
Find the values of each of the expression
Answer:
Let and
, so all ratio of y are positive and
and
Also,
as
So,
Hence,
Question 19.
Find the values of each of the expression
is equal to
A.
B.
C.
D.
Answer:
(For cos-1(cos x) type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range.)
So here,
Now, can be written as,
where [since, cos(π + x) = -cosx]
as cos-1(-x) = π – cos-1
Hence, .
Question 20.
Find the values of each of the expression
is equal to
A.
B.
C.
D. 1
Answer:
as
as
We all know that the principal value branch of sin-1 is
Therefore,
Hence, the value of
Question 21.
Find the values of each of the expression
is equal to
A. π
B.
C. 0
D.
Answer:
Miscellaneous Exercise
Question 1.Find the value of the following:
Answer:
(Forcos-1(cosx) type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range.)
So here,
Now, can be written as,
where
Hence,
Question 2.Find the value of the following:
Answer:
(For tan-1(tanx) type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range.)
So here,
Now, can be written as,
where, [since, tan(π+x) = tanx]
Hence,
Question 3.Prove that
Answer:Taking LHS
Let
Then,
Therefore,
……. (1)
and
As, LHS = RHS
Hence Proved !
Question 4.Prove that
Answer:
………………………. (1)
Let
Then,
………………………. (2)
Now,
L.H.S.
Putting the value from equation (1) and (2))
=R.H.S.
Hence Proved.
Question 5.Prove that
Answer:
Let
Then,
……………………….(1)
Let
Then,
……………(2)
Let
Then,
…………… (3)
Now,
L.H.S.
Putting the value from the equation (1) And (2))
……….by equation (3)
=R.H.S.
Hence Proved.
Question 6.Prove that
Answer:We can also solve this problem by using the identity Sin(A + B) = sinA cosB + cosA sinB
Letand
So,
sin A = 3/5 and cos B = 12/13
Therefore,
cos A = 4/5 and sin B = 5/13
As R.H.S. is sin-1 we will use sin (A+B)
= R.H.S.
Hence Proved.
Question 7.Prove that
Answer:
Let Then,
LetThen,
Now,
R.H.S. =
Putting the value from equation (1) and (2))
=L.H.S.
Hence Proved.
Question 8.Prove that
Answer:L.H.S.
= R.H.S.
Hence Proved.
Question 9.Prove that
Answer:
Let Then,
So now putting the value, we get,
R.H.S.
= L.H.S.
Question 10.Prove that
Answer:Consider,
On Rationalizing, we get,
Now,
L.H.S.
= R.H.S.
Hence Proved
Question 11.Prove that
Answer:
Letso that
Now,
L.H.S.
= R.H.S.
Hence Proved.
Question 12.Prove that
Answer:
Now, L.H.S.
Now, Let
L.H.S.
= R.H.S.
Hence Proved
Question 13.Solve the following equations:
Answer:
Hence,
Question 14.Solve the following equations:
Answer:
As we know,
We know,
So,
Hence,
Question 15.Solve the following equations:
is equal to
A.
B.
C.
D.
Answer:Let then
Question 16.Solve the following equations:
, then x is equal to
A.
B.
C. 0
D.
Answer:
Now we will put Now, we will put x= siny in the given equation, and we get,
⟹ 1 – siny = cos2y as
⟹ 1 - cos2y = sin y
⟹ 2sin2y = sin y
⟹ siny(2siny - 1) = 0
⟹ siny = 0 or 1/2
∴ x = 0 or 1/2
Now, if we put then we will see that,
L.H.S. =
R.H.S
Hence, is not the solution of the given equation.
Thus, x = 0
Question 17.Solve the following equations:
is equal to
A.
B.
C.
D.
Answer:
Find the value of the following:
Answer:
(Forcos-1(cosx) type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range.)
So here,
Now, can be written as,
where
Hence,
Question 2.
Find the value of the following:
Answer:
(For tan-1(tanx) type of problem we have to always check whether the angle is in the principal range or not. This angle must be in the principal range.)
So here,
Now, can be written as,
where, [since, tan(π+x) = tanx]
Hence,
Question 3.
Prove that
Answer:
Taking LHS
Let
Then,
Therefore,
……. (1)
and
As, LHS = RHS
Hence Proved !
Question 4.
Prove that
Answer:
………………………. (1)
Let
Then,
………………………. (2)
Now,
L.H.S.
Putting the value from equation (1) and (2))
=R.H.S.
Hence Proved.
Question 5.
Prove that
Answer:
Let
Then,
……………………….(1)
Let
Then,
……………(2)
Let
Then,
…………… (3)
Now,
L.H.S.
Putting the value from the equation (1) And (2))
……….by equation (3)
=R.H.S.
Hence Proved.
Question 6.
Prove that
Answer:
We can also solve this problem by using the identity Sin(A + B) = sinA cosB + cosA sinB
Letand
So,sin A = 3/5 and cos B = 12/13
Therefore,
cos A = 4/5 and sin B = 5/13
As R.H.S. is sin-1 we will use sin (A+B)
= R.H.S.
Hence Proved.
Question 7.
Prove that
Answer:
Let Then,
LetThen,
Now,
R.H.S. =
Putting the value from equation (1) and (2))
=L.H.S.
Hence Proved.
Question 8.
Prove that
Answer:
L.H.S.
= R.H.S.
Hence Proved.
Question 9.
Prove that
Answer:
Let Then,
So now putting the value, we get,
R.H.S.
= L.H.S.
Question 10.
Prove that
Answer:
Consider,
On Rationalizing, we get,
Now,
L.H.S.
= R.H.S.
Hence Proved
Question 11.
Prove that
Answer:
Letso that
Now,
L.H.S.
= R.H.S.
Hence Proved.
Question 12.
Prove that
Answer:
Now, L.H.S.
Now, Let
L.H.S.
= R.H.S.
Hence Proved
Question 13.
Solve the following equations:
Answer:
Hence,
Question 14.
Solve the following equations:
Answer:
As we know,
We know,
So,
Hence,
Question 15.
Solve the following equations:
is equal to
A.
B.
C.
D.
Answer:
Let then
Question 16.
Solve the following equations:
, then x is equal to
A.
B.
C. 0
D.
Answer:
Now we will put Now, we will put x= siny in the given equation, and we get,
⟹ 1 – siny = cos2y as
⟹ 1 - cos2y = sin y
⟹ 2sin2y = sin y
⟹ siny(2siny - 1) = 0
⟹ siny = 0 or 1/2
∴ x = 0 or 1/2
Now, if we put then we will see that,
L.H.S. =
R.H.S
Hence, is not the solution of the given equation.
Thus, x = 0
Question 17.
Solve the following equations:
is equal to
A.
B.
C.
D.
Answer: