EXERCISE 1.5PAGE 12
Balbharati solutions for Mathematics and Statistics 1 (Commerce) 12th Standard HSC Maharashtra State Board Chapter 1 Mathematical Logic Exercise 1.5 [Page 12]
Use quantifiers to convert the following open sentences defined on N, into a true statement.
x2 + 3x - 10 = 0
SOLUTION
∃ x ∈ N, such that x2 + 3x – 10 = 0
It is true statement, since x = 2 ∈ N satisfies it.
Use quantifiers to convert the following open sentences defined on N, into a true statement.
3x - 4 < 9
SOLUTION
∃ x ∈ N, such that 3x – 4 < 9
It is true statement, since
x = 2, 3, 4 ∈ N satisfies 3x - 4 < 9.
Use quantifiers to convert the following open sentences defined on N, into a true statement.
n2 ≥ 1
SOLUTION
∀ n ∈ N, n2 ≥ 1
It is true statement, since all n ∈ N satisfy it.
Use quantifiers to convert the following open sentences defined on N, into a true statement.
2n - 1 = 5
SOLUTION
∃ n ∈ N, such that 2n - 1 = 5
It is a true statement since all n = 3 ∈ N satisfy 2n - 1 = 5.
Use quantifiers to convert the following open sentences defined on N, into a true statement.
y + 4 > 6
SOLUTION
∃ y ∈ N, such that y + 4 > 6
It is a true statement since y = 3, 4, ... ∈ N satisfy y + 4 > 6.
Use quantifiers to convert the following open sentences defined on N, into a true statement.
3y - 2 ≤ 9
SOLUTION
∃ y ∈ N, such that 3y - 2 ≤ 9
It is a true statement since y = 1, 2, 3 ∈ N satisfy it.
If B = {2, 3, 5, 6, 7} determine the truth value of ∀ x ∈ B such that x is prime number.
SOLUTION
For x = 6, x is not a prime number.
∴ x = 6 does not satisfies the given statement.
∴ The given statement is false.
∴ It’s truth value is F.
If B = {2, 3, 5, 6, 7} determine the truth value of
∃ n ∈ B, such that n + 6 > 12.
SOLUTION
For n = 7, n + 6 = 7 + 6 = 13 > 12
∴ n = 7 satisfies the equation n + 6 > 12.
∴ The given statement is true.
∴ It’s truth value is T.
If B = {2, 3, 5, 6, 7} determine the truth value of
∃ n ∈ B, such that 2n + 2 < 4.
SOLUTION
There is no n in B which satisfies 2n + 2 < 4.
∴ The given statement is false.
∴ It’s truth value is F.
If B = {2, 3, 5, 6, 7} determine the truth value of
∀ y ∈ B, such that y2 is negative.
SOLUTION
There is no y in B which satisfies y2 < 0.
∴ The given statement is false.
∴ It’s truth value is F.
If B = {2, 3, 5, 6, 7} determine the truth value of
∀ y ∈ B, such that (y - 5) ∈ N
SOLUTION
For y = 2, y – 5 = 2 – 5 = –3 ∉ N.
∴ y = 2 does not satisfies the equation (y – 5) ∈ N.
∴ The given statement is false.
∴ It’s truth value is F.